Write an equation for a line perpendicular to y=-3x-5 and passing through the point (-9,-6)

Question

Write an equation for a line perpendicular to y=-3x-5 and passing through the point (-9,-6)

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    0
    2021-09-09T20:36:37+00:00

    The answer would be  y=13x+ -3.

    0
    2021-09-09T20:36:45+00:00

    The perpendicular slope would be the negative reciprocal of -3, which is \frac{1}{3}.

    Let’s see what the y-intercept should be, by finding one third of -6 and seeing how much we need to add or subtract to reach -9.

    1/3 times -9 is -3.

    To reach -6, we need to subtract 3.

    So, the y-intercept is 7.

    The equation is: y=\frac{1}{3} x -3.

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