Which functions have graphs that are less steep than the graph of f(x)=2×2 ? Select each correct answer. m(x)=3×2

Question

Which functions have graphs that are less steep than the graph of f(x)=2×2 ?

Select each correct answer.

m(x)=3×2

g(x)=−3×2

h(x)=−2×2

k(x)=x2

j(x)=−x2

0

Answers ( No )

    0
    2021-11-23T19:55:45+00:00

    Answer:

    k(x) = x^2 and j(x) = -x^2

    Step-by-step explanation:

    The higher the coefficient, the steeper the graph. So the ones that work have to be less than 2.

    It can’t be 3x^2 because 3 is greater than 2x^2.

    It can’t be -3x^2 because -3 is the same as 3 except on the other side of the graph, and 3 is greater than 2.

    It can’t be -2x^2 because it has equal steepness as 2x^2, except it’s on the opposite side of the graph.

    It is x^2 because 1 is less than 2 in 2x^2, so it’s less steep.

    It is -x^2 because -1 is the same as 1 except on the other side of the graph, and 1 is less than 2.

    Hope this helps!

    0
    2021-11-23T19:56:12+00:00

    We have been given few functions named

    m(x)=3x^2, g(x)=-3x^2, h(x)=-2x^2, k(x)=x^2, j(x)=-x^2

    We have to select those functions which are less steeper than  function f(x)=2x^2.

    To find that first we need to know what is the meaning of steepness.

    Steepness also means slope or gradient of the function.

    All the given functions have x^2. So we just need to compare the coefficients of each function.

    coefficient in f(x)=2x^2 is 2.

    Now we have to select functoin with less steepness.

    That means we have to select those functions whose absolute value of the coefficient is less than 2.

    Only function having absolute value of the coefficient less than 2 are:

    k(x)=x^2, j(x)=-x^2[/tex]

    Hence final answer is

    {k(x)=x^2, j(x)=-x^2[/tex] }

Leave an answer

Browse
Browse