which expression shows the correct multiplication of the following polynomilas? 3x(6x^2-3x+7)

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which expression shows the correct multiplication of the following polynomilas? 3x(6x^2-3x+7)

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    2021-10-11T07:39:00+00:00

    Answer: 18x^3-9x^2+21x

    Solution:

    3x(6x^2-3x+7)=

    Applying the distributive property in the multiplication to eliminate the parentheses:

    (3x)(6x^2)+(3x)(-3x)+(3x)(7)=

    (3*6)x^(1+2)+3*(-3)x^(1+1)+(3*7)x=

    18x^3-9x^2+21x

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