What is the initial value of the function represented by this graph? A coordinate grid is shown with x and y axes labeled from 0 to 7 at i

Question

What is the initial value of the function represented by this graph? A coordinate grid is shown with x and y axes labeled from 0 to 7 at increments of 1. A straight line joins the ordered pair 0, 2 with the ordered pair 7, 5. 0 1 2 5 Question 7(Multiple Choice Worth 5 points)

0

Answers ( No )

    0
    2021-09-06T13:38:05+00:00

    Answer:

    Option 3 rd is correct

    Initial value = 2

    Step-by-step explanation:

    A equation of line is given by:

    y =mx+b          ….[1]

    where

    m is the slope of the line and b is the y-intercept or the initial value

    As per the statement:

    A coordinate grid is shown with x and y axes labeled from 0 to 7 at increments of 1.

    It is also given that:

    A straight line joins the ordered pair (0, 2) with the ordered pair (7, 5)

    Calculate slope:

    using formula:

    \text{Slope (m)} = \frac{y_2-y_1}{x_2-x_1}

    Substitute the given ordered pairs we have;

    \text{Slope (m)} = \frac{5-2}{7-0}=\frac{3}{7}

    y-intercept states that the graph which cut y-axis.

    Substitute x =0 and solve for x:

    we have given with the ordered pair (0, 2)

    ⇒y-intercept(b) = 2

    Substitute the given values of m and b in [1]

    y = \frac{3}{7}x+2

    The equation of straight line  joins the ordered pair (0, 2) with the ordered pair (7, 5) is:

    y = \frac{3}{7}x+2

    The initial value of the function represented by the given graph as shown below is: 2

    0
    2021-09-06T13:38:11+00:00

    Answer:

    The initial value of the graph is 2. Third option is correct.

    Step-by-step explanation:

    It is given that A coordinate grid is shown with x and y axes labeled from 0 to 7 at increments of 1.

    The line is passing through the points (0,2) and (7,5).

    The point (0,2) is the y-intercept and graph labeled from 0 to 7, therefore 2 is the initial value.

    Slope of line is

    m=\frac{y_2-y_1}{x_2-x_1}=\frac{5-2}{7-0}=\frac{3}{7}

    The equation of line is

    y=mx+b

    Where, m is slope and b is y-intercept. So the equation of given line is

    y=\frac{3}{7}x+2

    At initial condition the value of x is 0. So, put x=0.

    y=\frac{3}{7}(0)+2=2

    Therefore the initial value of the graph is 2. Option 3 is correct.

Leave an answer

Browse
Browse