What is the equation of a line that passes through the points (-3,2) and (-5,8)

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What is the equation of a line that passes through the points (-3,2) and (-5,8)

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    2021-09-14T22:35:08+00:00

    To solve this problem, we have to start  with the general formula for the equation of a straight line.

    The equation of a straight line is y = mx+c

    where m is the gradient and c is the intercept on the y axis.

    The gradient is computed by m=\frac{y_2-y_1}{x_2-x_1}=\frac{8-2}{-5-(-3)} =\frac{6}{-2}=-3

    The next step is to find the value of c , by picking the point  (-3,2)  and substituting it into the equation above together with the gradient.

    2=(-3)\times(-3)+c\\=>c =-7.

    The equation of the line is

    y = -3x-7.

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