What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5?

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What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5?

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    2021-11-26T09:58:33+00:00

    A line perpendicular to y = (-2/3)x + 5 has a slope of (+3/2).

    Use the slope-intercept formula here, and find b:

    y = mx + b becomes 1 = (3/2)(8) + b.  Multiplying all terms by 2, we get

    2 = 24 + 2b.  Thus, 2b = -22, b = -11, and the equation of the line is y = (3/2)x – 11.

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