What is the equation for a geometric sequence with a first term of 4 and a second term of −8? an = 4(2)n − 1 ? an = 4(

Question

What is the equation for a geometric sequence with a first term of 4 and a second term of −8?

an = 4(2)n − 1 ?
an = 4(−2)n − 1 ?
an = 4(−12)n − 1 ?
or
an = 4(12)n − 1 ?

0

Answers ( No )

    0
    2021-11-26T10:28:49+00:00

    Answer:

    a_n=4(-2)^{n-1}

    Step-by-step explanation:

    The common ratio is -8/4 = -2. The general formula for the n-th term is …

    … an = a1·r^(n-1) . . . . . . note the use of the caret (^) and parentheses

    For r = -2 and a1 = 4, this becomes …

    an = 4·(-2)^(n-1) . . . . approximately matches the 2nd selection

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