what is the center of the circle given by the equation (x-2)^2 + (y+4)^2 = 6

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what is the center of the circle given by the equation (x-2)^2 + (y+4)^2 = 6

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    0
    2022-01-05T22:58:21+00:00

    The equation of circle with center (g,f) and radius r is given by,
    (x-g)² + (y-f)² = r²

    Now, compare equation (x-2)² + (y+4)² = 6 with the above equation.
    g = 2 and f = -4
    Therefore, center of the circle is (2,-4)

    0
    2022-01-05T22:58:26+00:00

    Answer: 2,-4 is the answer

    Step-by-step explanation:

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