What are the solutions of the quadratic equation? 2x^2 – 16x + 32 = 0 show all work

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What are the solutions of the quadratic equation? 2x^2 – 16x + 32 = 0 show all work

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    0
    2021-10-04T12:22:25+00:00

    first , to make it easier to factor divide by 2:-

    2(x^2 – 8x + 16) = 0

    2(x – 4)(x – 4) = x

    x – 4 = 0  to x = 4 Answer

    Because a quadratic equation has to have 2 solutions  we say that x = 4 Duplicity 2.

    0
    2021-10-04T12:23:04+00:00

    Answer:

    x= 4 x=-4

    Step-by-step explanation:

    In order to solve this we first have to factorize the equation, to make it solvable, as you can see all of the terms are multiples of 2 so we first factorize by dividin all of them by 2:

    2x^2-16x+32=0

    2(x^2-8x+32)=0

    No we just factorize the perfect square trinomial that is left inside the parenthesis:

    2(x-4)(x+4)=0

    So the two solutions for x would be -4 and 4.

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