Use the three steps to solve the problem. Betty has 10 more dimes than quarters. If she has $3.45, how many coins does she have?

Question

Use the three steps to solve the problem. Betty has 10 more dimes than quarters. If she has $3.45, how many coins does she have?

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    0
    2021-09-09T19:17:54+00:00

    Step 1——-> set variables.
    Let
    x———–> number of dimes
    y———–> number of quarters 

    Step 2:  set the equation and solve for the variable
    we know that
    0.10 x+0.25 y=3.45—————> 10x+25y=345   equation (1)
    x=y+10  equation (2)
    substituting 2 in 1
    10[y+10]+25y=345—-> 10y+100+25y=345
    35y=345-100———–> y=245/35=7
    x=y+10——–> x=7+10=17

    Step 3:  plug in the value of x and y from last step into the variables.

    y=7——–> number of quarters coins
    x=17——-> number of dimes coins

    She has (7+17)=24 coins in total

    0
    2021-09-09T19:18:17+00:00

    If we assume the quarters are x, then the dimes are 10+x
    Thus, 0.25x + 0.1(10+x) = 3.45
             = 0.25x +1 +0.1 x = 3.45
            = 0.35 x = 3.45 -1
             = 0.35x = 2.45
                       x = 7
    Therefore, the quarters are 7, while the dimes were 17,
    Thus a total of 24 coins

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