## Use the three steps to solve the problem. Betty has 10 more dimes than quarters. If she has $3.45, how many coins does she have?

Question

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## Answers ( No )

Step 1——->set variables.Let

x———–> number of dimes

y———–> number of quarters

Step 2: set the equation and solve for the variablewe know that

0.10 x+0.25 y=3.45—————> 10x+25y=345 equation (1)

x=y+10 equation (2)

substituting 2 in 1

10[y+10]+25y=345—-> 10y+100+25y=345

35y=345-100———–> y=245/35=7

x=y+10——–> x=7+10=17

Step 3: plug in the value of x and y from last step into the variables.y=7——–> number of quarters coins

x=17——-> number of dimes coins

She has (7+17)=24 coins in total

If we assume the quarters are x, then the dimes are 10+x

Thus, 0.25x + 0.1(10+x) = 3.45

= 0.25x +1 +0.1 x = 3.45

= 0.35 x = 3.45 -1

= 0.35x = 2.45

x = 7

Therefore, the quarters are 7, while the dimes were 17,

Thus a total of 24 coins