There are ten cards, each has a different number on it, from 1 to 10. Sam took one card, and it was 5 on it. If he takes one of the remainin

Question

There are ten cards, each has a different number on it, from 1 to 10. Sam took one card, and it was 5 on it. If he takes one of the remaining cards without looking, what is the probability that the sum of the numbers on his two cards will be smaller than 8?

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    0
    2021-10-11T05:43:44+00:00

    there are 9 cards left

    1,2,3,4,6,7,8,9,10

    the only cards that will make the sum less than 8 is 1 and 2

    2/9

    Answer: 2/9

    0
    2021-10-11T05:43:49+00:00

    Answer:

    2/9

    Step-by-step explanation:

    The original group of cards consisted of: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

    He took a 5.

    The current group of cards consists of: 1, 2, 3, 4, 6, 7, 8, 9, 10

    Which cards can he take and have a sum less than 8?

    5 + 1 = 6   good

    5 + 2 = 7    good

    5 + 3 = 8    not good

    Only the cards with 1 or 2 are good.

    There are 9 cards remaining, and he gets the desired outcome from only 2 of those cards.

    p(sum less than 8) = 2/9

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