the population at Saint Maria High increased from 1800 students ten years ago to 1926 students last year. What was the percent increase?

Question

the population at Saint Maria High increased from 1800 students ten years ago to 1926 students last year. What was the percent increase?

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    0
    2021-10-14T22:37:33+00:00

    It’s a 7% increase. When you want to find percent increase/decrease, you want to subtract the numbers of the before and after. In this case, subtract 1926 and 1800, which will equal 126. Then, percent over 100 would be the first fraction, but since you don’t know the percent, put x. The second fraction is the amount of change over the original number. In this case, the amount of change will be 126 and the original is 1800. x/100=126/1800 now you just cross multiply and solve. You will end up with 7

    0
    2021-10-14T22:37:39+00:00

    Answer:

    The percent increase in the population of Saint Maria High is:

    7%

    Step-by-step explanation:

    Percent increase is given by:

     \dfrac{New-Original}{Original}\times 100

    New value=1926

    Original value=1800

    Percent increase=

    \dfrac{1926-1800}{1800}\times 100

    = \dfrac{126}{18} \\\\=7%

    Hence, The percent increase in the population of Saint Maria High is:

    7%

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