The floor of a rectangular deck has a length that is 6 feet more than it’s width, x. Hakeem is building the deck and decided to increase bot

Question

The floor of a rectangular deck has a length that is 6 feet more than it’s width, x. Hakeem is building the deck and decided to increase both dimensions by 3 feet. What is the new area, D, of the floor of the deck?

A. x^2 + 12x + 27
B. x^2 + 9x + 18
C. x^2 + 9x
D. x^2 +6x

0

Answers ( No )

    0
    2021-09-09T17:51:59+00:00

    Let the width of the rectangular deck be = x feet

    The length is 6 feet more than the width so length is = x+6 feet

    Let us assume that a total 3 feet is increased (1.5 feet on both ends)

    As Hakeem decided to increase both dimensions by 3 feet, this means 1.5 feet is increased on both sides of the deck. So, length and width increases by 3 feet each.

    Hence, new length is = x+6+3 = x+9 feet

    New width is = x+3 feet

    So new area = length*width

    D = (x+9)(x+3)

    = x^{2}+3x+9x+27

    = x^{2}+12x+27 square feet

    Hence, option A is correct.

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