## The ages of three family children can be expressed as consecutive integers. the square of the age of the youngest child is 4 more than eight

Question

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## Answers ( No )

Let the middle child be x

youngest child = x – 1

Oldest child = x + 1

(x – 1)^2 = 8(x + 1) + 4

x^2 – 2x + 1 = 8x + 8 + 4

x^2 – 10x – 11 = 0

(x – 11) * (x + 1) = 0

X = – 1 makes no sense. How can a middle child be – 1 years old?

x = 11

The youngest child is 10

The middle child is 11

The oldest child is 12

Check

=====

10^2 = 100

(8*12) + 4

96 + 4 = 100 So the results have been checked.