suppose a skydiver (mass = 75kg) is falling toward the Earth. When the skydiver is 100m above the earth he is moving 60m/s. At this point c

Question

suppose a skydiver (mass = 75kg) is falling toward the Earth. When the skydiver is 100m above the earth he is moving 60m/s. At this point calculate the skydivers…….

Gravational potential energy

Kinetic energy

0

Answers ( No )

    0
    2021-11-23T18:55:37+00:00

    From the question,
    The mass of the skydiver,

    m=75kg

    The height from the Earth at which the skydiver is before falling,

    h=100m

    Velocity, V of the skydiver

    =60m {s}^{ - 1}

    Let us take acceleration due to gravity to be ;
    g = 10m {s}^{ - 2}

    The mass of the skydiver, m=75kg

    The height from the Earth at which the skydiver is before falling, h=100m

    Velocity, V of the skydiver =60m/s

    Potential energy, P.E can be calculated from the relation;
    P.E = mgh

    P.E =75kg \times 10m {s}^{ - 2}  \times 100m
    P.E =75000 J

    Therefore, the gravitational potential energy of the skydiver is 75000 J

    Kinetic energy,K.E
     =  \frac{1}{2}m {v}^{2}

     =  \frac{1}{2} \times 75 kg\times ( {60})^{2} m {s}^{ - 1}

    =135000 J

    Hence the kinetic energy of the Skydiver is 135000 J

    0
    2021-11-23T18:56:16+00:00

    Answer:

    Kinetic energy  = 135 kJ

    Potential energy = 73.5 kJ

    Explanation:

     Mass of sky diver = 75 kg

      Velocity = 60 m/s

       Height = 100 m

     Kinetic energy is given by the expression, KE = \frac{1}{2} mv^2, where m is the mass and v is the velocity.

      So Kinetic energy  = \frac{1}{2} *75*60^2=135000J=135kJ

     Potential energy is given by the expression, PE =mgh, m is the mass, g is the acceleration due to gravity value and h is the height.

     So, Potential energy = 75*9.8*100 = 73500J = 73.5 kJ

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