In the equation square root n+5-square root n-10=1 the value of n is

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In the equation square root n+5-square root n-10=1 the value of n is

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    0
    2021-09-06T10:54:52+00:00

    Answer:

    the value of n is 59

    Step-by-step explanation:

    plato says it was right (:

    0
    2021-09-06T10:55:06+00:00

    square root n+5-square root n-10=1

    \sqrt{n+5} - \sqrt{n-10} =1

    add sqrt(n-10) on both sides

    \sqrt{n+5} =1+ \sqrt{n-10}

    To remove square root we take square on both sides

    (\sqrt{n+5})^2 =(1+ \sqrt{n-10})^2

    n+5=(1+ 2\sqrt{n-10} +n -10)

    n+5=2\sqrt{n-10} +n -9

    Subtract n  and add 9 on both sides

     14=2\sqrt{n-10}

    Now we divide both sides by 2

    7=\sqrt{n-10}

    Take square on both sides

     +-49= n – 10

    49 = n-10   and -49 = n – 10

    Add 10 on both sides

    n= 59   and n = -39

    Now we verify both solutions

    When n = -39 we will get negative under the square root . that is complex so we ignore n=-39

    n = 59 is our solution

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