If there is only one solution to the equation 0=-x^2 + bx -8 what are the possible values of b?

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If there is only one solution to the equation 0=-x^2 + bx -8 what are the possible values of b?

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    2021-10-11T05:27:53+00:00

    Answer:

     b = 4\sqrt{2} ,  b = -4\sqrt{2}

    Step-by-step explanation:

    For a single solution, you must have a perfect square trinomial.

     -x^2 + bx - 8 = 0

     x^2 - bx + 8 = 0

     (x - \sqrt{8})^2 = 0

     x^2 - 2\sqrt{8}x + 8 = 0

     x^2 - 4\sqrt{2}x + 8 = 0

     -x^2 + 4\sqrt{2}x - 8 = 0

     b = \pm 4\sqrt{2}

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