How much pure maple syrup should be added to 36 tablespoons of a 45% solution in order to obtain a 60% solution

Question

How much pure maple syrup should be added to 36 tablespoons of a 45% solution in order to obtain a 60% solution

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    0
    2021-11-26T13:45:57+00:00

    (36(0.45) + x)/(x+36) = 0.6,
    x + 16.2 = 0.6x + 21.6,
    x = 13.5 grams of pure syrup should be added

    0
    2021-11-26T13:46:24+00:00

    Let’s assume

    number of teaspoons of pure maple syrup=x

    now, we can find maple syrup content of pure syrup

    so,

    maple syrup content of pure syrup=1.00*x

    36 tablespoons of a 45% solution

    so,

    male syrup content of 45% =45% of 36

    male syrup content of 45%  =\frac{45}{100} *36

    male syrup content of 45%  =0.45*36

    so,

    total mixture solution =x+36

    total maple syrup=60% of (x+36)

    and we can also find total maple syrup

    total maple syrup =maple syrup content of pure syrup +male syrup content of 45%

    total maple syrup  =1.00x+0.45*36

    now, we can set it equal

     0.60(x+36)=1.00x+0.45*36

    now, we can solve for x

     0.60x+0.60*36=1.00x+0.45*36

     0.60*36-0.45*36=1.00x-0.60x

     0.40x=0.60*36-0.45*36

     0.40x=0.15*36

     x=13.5

    so, 13.5 teaspoons pure maple syrup should be added to 36 tablespoons of a 45% solution in order to obtain a 60% solution……….Answer

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