## How much pure maple syrup should be added to 36 tablespoons of a 45% solution in order to obtain a 60% solution

Question

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## Answers ( No )

(36(0.45) + x)/(x+36) = 0.6,

x + 16.2 = 0.6x + 21.6,

x = 13.5 grams of pure syrup should be added

Let’s assume

number of teaspoons of pure maple syrup=x

now, we can find maple syrup content of pure syrup

so,

maple syrup content of pure syrup=1.00*x

36 tablespoons of a 45% solution

so,

male syrup content of 45% =45% of 36

male syrup content of 45%

male syrup content of 45%

so,

total mixture solution =x+36

total maple syrup=60% of (x+36)

and we can also find total maple syrup

total maple syrup =maple syrup content of pure syrup +male syrup content of 45%

total maple syrup

now, we can set it equal

now, we can solve for x

so,

13.5 teaspoonspure maple syrup should be added to 36 tablespoons of a 45% solution in order to obtain a 60% solution……….Answer