How many different four-digit numbers can be made using the digits 1, 2, 3, 4, 5, 6 if no digit can be used more than once?

Question

How many different four-digit numbers can be made using the digits 1, 2, 3, 4, 5, 6 if no digit can be used more than once?

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    2021-09-14T20:26:22+00:00

     To solve this problem you must use Permutation:
     
     You want to made 4 digit numbers with the digits 1, 2, 3, 4, 5, 6 and no digit can be used more than once. So, we have:
     
     (A,B,C,D)

     A can variate in six (6) differents forms.
     B can variate in (6-1)=5 differents forms.
     C can variate 4 digits.
     D can variate 3 digits.
     
     Keeping this on mind, we have:
     
     =6!/2!
     =6*5*4*3
     =360
     
     The answer is: 360

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