For what natural values of n is the difference (2−2n)−(5n−27) positive?

Question

For what natural values of n is the difference (2−2n)−(5n−27) positive?

0

Answers ( No )

    0
    2021-09-09T01:59:08+00:00

    (2−2n)−(5n−27) >0

    distribute

    2-2n -5n +27 >0

    combine like terms

    -7n +29 >0

    subtract 29 from each side

    -7n> -29

    divide by -7  (flips the inequality)

    n < -29/-7

    n <4.14

    natural numbers are 1,2,3,4……

    n must be 1,2,3,4

    Answer: 1,2,3,4

    0
    2021-09-09T01:59:27+00:00

    (2 – 2n) – (5n -27) > 0

    -7n +27 + 2 > 0

    -7n > -29

    n < 29/7 < 4.143

    So  the natural values of n to make the expression positive are

    1, 2, 3 and 4  (answer)

Leave an answer

Browse
Browse