## Find two additional roots of P(x)=0. 13+sqrt 3 and 7i

Question

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## Answers ( No )

so, x = 13, x = √3 and x =7i.

now, recall that for an EVEN radical, there are two possible roots, namely is say √3 is say hmmm some value “a”, that means that a*a = √3, however, -a*-a is also √3, therefore, ±√3 are two valid values, and therefore -√3 is another one.

now…. keep in mind that, complex solutions or roots, never come all by their lonesome, their sister is always with them, the

conjugate, so, for 7i or namely 0 + 7i, her sister is always around, 0 – 7i, which is the other root.