## Find the volume of a box that will hold nine 9.425 cm3 cylindrical containers that each measure 3 centimeters long. (round to nearest whole

Question

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Lorem ipsum dolor sit amet, consectetur adipiscing elit.Morbi adipiscing gravdio, sit amet suscipit risus ultrices eu.Fusce viverra neque at purus laoreet consequa.Vivamus vulputate posuere nisl quis consequat.

## Answers ( No )

To find the volume of a box that would hold these nine cylinders, you would start with the formula for volume of a cylinder. V=pi x r^2 x h. Substitute in the known volume and the known Height. 9.425=pi x r^2 x 3. Divide both sides by three to get approximately 3.143 = pi x r^2. Divided by pi on both sides. This leaves you with one = r^2. So the radius is equal to one. If the radius equals one, the diameter is two. Assuming the cylinders are arranged in a 3 x 3 array, the length and width of the rectangle or box would be 6cm x 6cm. To find the volume of the box necessary, multiply the length of six by the width of six by the height of three. The volume would be 108 square cm.