## Find the volume of a box that will hold nine 9.425 cm3 cylindrical containers that each measure 3 centimeters long. (round to nearest whole

Question

Find the volume of a box that will hold nine 9.425 cm3 cylindrical containers that each measure 3 centimeters long. (round to nearest whole number)

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## Answers ( No )

1. To find the volume of a box that would hold these nine cylinders, you would start with the formula for volume of a cylinder. V=pi x r^2 x h. Substitute in the known volume and the known Height. 9.425=pi x r^2 x 3. Divide both sides by three to get approximately 3.143 = pi x r^2. Divided by pi on both sides. This leaves you with one = r^2. So the radius is equal to one. If the radius equals one, the diameter is two. Assuming the cylinders are arranged in a 3 x 3 array, the length and width of the rectangle or box would be 6cm x 6cm. To find the volume of the box necessary, multiply the length of six by the width of six by the height of three. The volume would be 108 square cm.