find the equation of the circle with center at (-3,1) and through the point (2,13)

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find the equation of the circle with center at (-3,1) and through the point (2,13)

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    2021-09-10T15:58:47+00:00

    Try this option:
    1. if centre of the circle is O(-3;1) and P(2;13), then OP=√(5²+12²)=13=r (radius);
    2. in common view an equation of the circle is: (x-a)²+(y-b)²=r², where (a;b) is the centre.
    Using this: (x+3)²+(y-1)²=13² 

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