An equation of a parabola with its vertex at (-3,2) and focus at (-3,-1) written in general equation form

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An equation of a parabola with its vertex at (-3,2) and focus at (-3,-1) written in general equation form

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    2021-09-10T05:31:13+00:00

     we have that
    standard form of equation for parabola:
     (x-h)^2=-4p(y-k)
    (h,k) ———>being the (x,y) coordinates of the vertex.
    Parabola opens downwards because focus is below vertex on the axis of symmetry.
    For given problem:
    vertex: (-3,2)
    axis of symmetry: x=-3
    p=distance from vertex to focus on the axis of symmetry=2-(-1)=3
    4p=12
    Directrix: y=2+p=5
    Equation:
    (x+3)^2=-12(y-2)

    the answer is (x+3)^2=-12(y-2)

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