According to the fundamental theorem of algebra, how many zeros does the function f(x) = 4×3 – x2 – 2x + 1 have? A) 1 B)2<

Question

According to the fundamental theorem of algebra, how many zeros does the function f(x) = 4×3 – x2 – 2x + 1 have?

A) 1
B)2
C)3
D)4

0

Answers ( No )

    0
    2021-09-08T22:30:29+00:00

    Answer: c)3 roots

    Step-by-step explanation:

    According to the fundamental theorem of algebra, any polynomial expression of degree n has n roots.

    So, in this case:

    f(x) = 4×3 – x2 – 2x + 1

    The degree of the polynomial expression is given by the highest exponent on a variable. The term that has the highest exponent is 4x∧3.

    Since the degree of the polynomial is 3, it has 3 roots.

    0
    2021-09-08T22:31:03+00:00

    Hello from MrBillDoesMath!

    Answer   C)     (or 3 )

    Discussion:  f(x) is an equation of degree 3 as the highest exponent of “x” is the number 3.   The fundamental theorem tell us there are 3 zeroes or roots but not about their character (e.g. are they all real? real and complex?)

    Regards, MrB.

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