A singles tennis court is a rectangle 27 feet wide and 78 feet long. Suppose a player at corner A hits the ball to her opponent in the diago

Question

A singles tennis court is a rectangle 27 feet wide and 78 feet long. Suppose a player at corner A hits the ball to her opponent in the diagonally opposite corner B. Approximately how far does the ball travel, to the nearest tenth of a foot?

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    2021-09-06T08:45:56+00:00

    Basically, you just have to find the length of the rectangle that is 27 x 78 feet.
    The equation for the diagonal: 
    d = sqrt(l^2+w^2)
    l = 27
    w = 78
    plug them in and solve
    d = sqrt ( (27^2) + (78^2) )
    d = sqrt ( 729 + 6084 )
    d = sqrt ( 6813 )
    ≈ 82.5

    The ball traveled approximately 82.5 feet from one corner of the rectangular 27 x 78 foot field, diagonally to the other side.

    Hope this helps

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