A minor league baseball team plays 101 games in a season. If the team won 14 more than twice as many games as they lost, how many wins and l

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A minor league baseball team plays 101 games in a season. If the team won 14 more than twice as many games as they lost, how many wins and loses did the team have?

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    2021-09-19T05:18:28+00:00

    A minor league plays 101 games,
    They win 14 more than twice as many as they lost.
    How many wins and loses?

    Okay, simple.
    First, write a simple addition equation. In this case wins = w and losses = l.
    l + w = 101.

    Now, we have to figure out a way to make one of the terms the same term as the other, in this case we can change the terms of w to l.
    l = l
    w = 2l +14 (14 more than twice the amount)

    Okay. So plug in the new amount for w.
    l + 2l + 14 = 101. Great! we now have a simple equation. lets solve.
    put similar terms together.
    3l + 14 = 101
    3l = 87
    l = 29
    So, we have 29 loses, and
    w = 2(29) + 14
    72 wins!
    To check,
    72 + 29 = 101, correct!

    Hope this helps!

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