33 times a number xxx, subtracted from 181818, is less than -90.?90.Minus, 90, point Write an inequality for the statement above. Find the s

Question

33 times a number xxx, subtracted from 181818, is less than -90.?90.Minus, 90, point Write an inequality for the statement above. Find the solution set of the inequality. Write the solution using a fraction or integer.

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    2021-10-14T22:34:54+00:00

    Answer:

    Let the number be x.

    Given: 33 times a number x, subtracted from 18, is less than -90.

    we can write this statement in inequality form, i.e,

    18-33x<-90

    Now, to find the solution set for this inequality:-

    18-33x<-90

    Subtraction poperty of equality states that you subtract the same number from both sides of an equation.

    Subtract  18 from both sides,

    18-33x-18<-90-18

    Simplify:

    -33x<-108

    Multiply both sides by -1 (reverse the inequality)

    (-1)(-33x)>(-108)(-1) or

    33x>108

    Divide both sides by 33, we get

    \frac{33x}{33}= \frac{108}{33}

    Simplify:

    x>\frac{36}{11}

    Therefore, the solution set for this inequality is,  (\frac{36}{11} ,\infty ) [

    The solution using a fraction or integer is, tex]x>\frac{36}{11}[/tex] 0r x>3\frac{3}{11}

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