3. y=37x+11y=37x+11 -3x + 7y = 13 Part A: Convert the second equation to slope-intercept form. Show your work! Part B: Determine whet

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3. y=37x+11y=37x+11 -3x + 7y = 13 Part A: Convert the second equation to slope-intercept form. Show your work! Part B: Determine whether or not the graphs of the lines are parallel. Explain how you know.

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    2021-10-13T22:18:52+00:00

    We are given first equation y=\frac{3}{7}x+11.

    Second equation is -3x + 7y = 13.

    Part A: We need to convert that second equation in slope-intercept form y=mx+b.

    In order to convert it in slope-intercept form, we need to isolate it for y.

    -3x + 7y = 13

    Adding 3x on both sides, we get

    -3x+3x + 7y = 3x+13

    7y = 3x +13.

    Dividing both sides by 7, we get

    7y/7 = 3x/7 +13/7.

    y= 3/7 x + 13/7.

    Slope for first equation y=3/7 x +11 is 3/7 and slope of second equation y= 3/7 x + 13/7 is also 3/7.

    Slopes are same for both equations.

    Part B: Therefore, lines are parallel due to equal slopes.

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